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Sonbull [250]
3 years ago
12

PLEASE HELP!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
brilliants [131]3 years ago
8 0

9514 1404 393

Answer:

  the sum of the interior angles is not 360°

Step-by-step explanation:

In order for the tiles to fit as shown, the sum of their interior angles must be 360°. Each n-sided figure has an interior angle sum of ...

  180° - 360°/n

Then the sum of interior angles of 5-, 6-, and 8-sided figures will be ...

  (180° -360°/5) +(180° -360°/6) +(180° -360°/8) = 540° -360°(1/5 +1/6 +1/8)

  = 540° -360°(59/120) = 363° ≠ 360°

The angle sum is incorrect, so the tiles will overlap or leave a gap. They will not fit together perfectly.

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The base of a parallelogram is four times its height. If the area of the parallelogram is 324 cm2, find the base and height.
madam [21]
A = bh
b = 4h
A = 324

324 = 4h * h
324 = 4h^2
324/4 = h^2
81 = h^2
sqrt 81 = h
9 = h

b = 4h
b = 4(9)
b = 36

so the height (h) = 9 cm and the base (b) = 36 cm
8 0
3 years ago
At Blanca stables there are 20 stallions and 14 mates at Logan’s stables there are 10 stallions and 7 mates which ratio is highe
polet [3.4K]

Answer:

The ratio is the same

Step-by-step explanation:

Bianca- 20:14

= 10:7

Logan- 10:7

The ratio is the same

3 0
3 years ago
What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? Round your answer to
yuradex [85]
Hello!

The Correct Answer to this would be 100%:

Option "85.4".

(Work Below)

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2 
10 m = √ [ 6m( 2 x radius - 6 m ) ] 
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ² 
100 m² = 6 m( 2 x radius - 6 m ) 
100 m² = 12 m x radius - 36 sq m 
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m² 
136 m² = 12 m x radius 
136 m² / 12 m = 12 m x radius / 12 m 
<span>11.333 m = radius 
</span>
the area beneath an arc: 

Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ). 
</span>
r² = (11.333 m)² = 128.444 m² 
r - h= 11.333 m - 6 m = 5.333 m 
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ] 

Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ] 

Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m 

Area = 138.828 m² - 53.333 m² 

Area = 85.4 m<span>²
</span>

Hope this Helps! Have A Wonderful Day! :)


And as Always...

7 0
3 years ago
Factor each completely.
Natasha_Volkova [10]

HI I JUST DID THE FIRST ONE . SORRY I CAN'T ANSWER THE 5TH AND6th IT'S HARD

3 0
4 years ago
Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum
const2013 [10]

Answer:  The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

S=\sum_{i=1}^{\infty}15(4)^{i-1}.

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, \sum_{i=1}^{\infty}a_i is an infinite series, with complex coefficients a_i and we consider the following limit:

L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.

Then, the series will be convergent if  L < 1 and divergent if  L > 1.

For the given series, we have

a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.

So, the limit is given by

L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0
4 years ago
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