Answer:
0.9007 is the probability that a student scored below 86 on this exam.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 77
Standard Deviation, σ = 7
We are given that the distribution of examination grades is a bell shaped distribution that is a normal distribution.
Formula:
a) P(student scored below 86)
P(x < 86)
Calculation the value from standard normal z table, we have,
0.9007 is the probability that a student scored below 86 on this exam.
Answer:
x = 58°, y = 32°
Step-by-step explanation:
all sides are equal, hence it is a rhombus.
in a rhombus, diagonals meet at 90degree..
hence in triangle,
58 + 90 + z = 180 (asp of a triangle.)
z = 32
y = z ( alternate interior angles as lines are parallel in rhombus)
y = 32
in the bigger triangle,
angles opposite to equal sides are equal, hence,
32 + 32 + (58 + x) = 180 ( angle sum property of a triangle,)
hence, x = 58
therefore,
x = 58°, y = 32°
68% is 0.68 and 17/25
3/8 is 0.375 and 37.5%
0.875 is 87.5% and 7/8
alyssa got 40% right
4m+t is -18
t/mr is 1/6 or 0.16 repeating
3m-5t is -2
mt/r is -2
Here, formula: 5h²
Coefficient = 5
Hope this helps!
