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mojhsa [17]
4 years ago
14

Select one: a. A, B, C b. A, D c. B, C d. A, D, E e. A, D, F

Mathematics
2 answers:
vazorg [7]4 years ago
4 0
I believe it would be B
yulyashka [42]4 years ago
4 0
It  will  be  A   I  HOPE  THIS     will   help you    i    not  great at  math  so   i had this question before  long time ago  ,3
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John Calipari, head basketball coach for the 2012 national champion University of Kentucky Wildcats, is the highest paid coach i
MrRissso [65]

Answer:

A) sample mean = $1.36 million

B) standard deviation = $0.9189 million

C) confidence interval = ($1.93 million , $0.79 million)

*since the sample size is very small, the confidence interval is not valid.

Step-by-step explanation:

samples:

  1. $2.7 million
  2. $2.4 million
  3. $2.2 million
  4. $2 million
  5. $1.5 million
  6. $1.5 million
  7. $0.5 million
  8. $0.5 million
  9. $0.2 million
  10. $0.1 million

sample mean = $1.36 million

the standard deviation:

  • $2.7 million - $1.36 million = 1.34² = 1.7956
  • $2.4 million - $1.36 million = 1.04² = 1.0816
  • $2.2 million - $1.36 million = 0.84² = 0.7056
  • $2 million - $1.36 million = 0.64² = 0.4096
  • $1.5 million - $1.36 million = 0.14² = 0.0196
  • $1.5 million - $1.36 million = 0.14² = 0.0196
  • $0.5 million - $1.36 million = -0.86² = 0.7396
  • $0.5 million - $1.36 million = -0.86² = 0.7396
  • $0.2 million - $1.36 million = -1.16² = 1.3456
  • $0.1 million - $1.36 million = -1.26² = 1.5876
  • total $8.444 million / 10 = $0.8444 million

standard deviation = √0.8444 = 0.9189

95% confidence interval = mean +/- 1.96 standard deviations/√n:

$1.36 million + [(1.96 x $0.9189 million)/√10] = $1.36 million + $0.57 million = $1.93 million

$1.36 million - $0.57 million = $0.79 million

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3 years ago
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Elan Coil [88]

Answer:

24

Step-by-step explanation:

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32.45 x 827.33 help??
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26,846.8585 is the awnser
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Please help with this if you don’t know don’t answer
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Answer:

3\16

Step-by-step explanation:

movement of snail per hour,1/8×3/2=3/16

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Solve 2x2 − 12x + 20 = 0. (5 points) 3 ± i 3 ± 2i 1 ± 2i 2 ± 3i
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