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Furkat [3]
3 years ago
14

A bicycle store costs $2600 per month to operate. The store pays an average of $55 per bike. The average selling price of each b

icycle is $95. How many bicycles
must the store sell each month to break even?
Mathematics
1 answer:
KatRina [158]3 years ago
3 0

Answer:

58

Step-by-step explanation:

95 - 55 = 45

2600 / 45 = 57.77778.....

Because you can't sell 0.777778 of a bike you instead sell 58

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At the end of April, Mandy told Bill that she has read 16 books this year and reads 2 books each month. Bill wants to catch up t
klemol [59]
Mandy Increases her books by 2 per month.
Bill increases his books by 4 per month.

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May          18          4
June         20          8
July          22        12
August     24        16
Sept        26        20
Oct          28        24
Nov          30        28
Dec        32          32
At the end of December they will have read the same amount of books.
6 0
3 years ago
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When a linear function has a slope of 5, what is the "run" part of the slope?
alukav5142 [94]
Slope equals rise over the run
so if slope = 5 then the rise also equals 5 and the run is 1


7 0
3 years ago
If the volume of a cone is 12.56, and the height is 3. What is the radius of the cone? R=
Alina [70]

Answer:

you can find a radius through its volume and height. Multiply the volume by 3. For example, the volume is 20. Multiplying 20 by 3 equals 60

Step-by-step explanat                      

I hope to help you

5 0
2 years ago
Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
3 years ago
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The sum of the angle measures of any triangle is 180 degrees. Angle 2 is twice the measure of angle 1. Angle 3 is 15 degrees les
allochka39001 [22]

Answer:

Angle 1 = 39, Angle 2 = 78 , Angle 3 = 63

Step-by-step explanation:

78/2 = 39

(Angle 2/2 = Angle 1)

78 - 15 = 63

(Angle 2 - 15 = Angle 3)

39 + 78 + 63 = 180

(Angle 1 + Angle 2 + Angle 3 = 180)

7 0
3 years ago
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