3 years ago

How to solve proportions

1 answer:

6 0

Step-by-step explanation:

stating the ratios as fractions, setting the two fractions equal to each other, cross-multiplying, and solving the resulting equation

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What is the solution to 3 + 4e^x+1 = 11?

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What is the solution to 3 + 4e^x+1 = 11?

Solution:

$3+4e^{x+1}=11$

To solve for x, Let us subtract 3 from both sides

$3+4e^{x+1}-3=11-3$

$0+4e^{x+1}=8$

$4e^{x+1}=8$

Let us divide by 4 on both sides

$\frac{4e^{x+1}}{4} =\frac{8}{4}$

$\frac{1e^{x+1}}{1} =\frac{2}{1}$

$e^{x+1} =2$

Let us take ln on both sides

$ln (e^{x+1}) =ln(2)$

So, x+1=ln(2)

To solve for x, Let us subtract 1 from both sides

x+1-1=ln(2) -1

x+0=ln(2)-1

x= ln(2) -1

Answer: Option (A)

x=ln(2)-1

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