Answer:

Step-by-step explanation:
To find the distance between any two points, we can use the distance formula:

Our first point, A, is at (1, 1) and our second point, B, is at (-2, 8).
Let's let A(1, 1) be (x₁, y₁) and B(-2, 8) be (x₂, y₂). Substitute this into the distance formula:

Subtract:

Square:

Add:

This cannot be simplified.
So, the distance between the two points is √58 or about 7.6 units.
And we're done!
So... where's my cookie :)?
crosses x-axis at (2, 0 ) and y-axis at (0, - 4 )
To find where the graph crosses the x and y axes ( intercepts )
• let x = 0, in the equation for y- intercept
• let y = 0, in the equation for x- intercept
x = 0 : y = 0 - 4 = - 4 ⇒ (0, - 4 )
y = 0 : 2x - 4 = 0 ⇒ 2x = 4 ⇒ x = 2 ⇒ (2, 0 )
Answer:
The answer here would be 0.
Step-by-step explanation:
If a and b are both equal distances from 0, then adding the together would equal 0. Since a is the inverse of b, using any number and its inverse will show you why the answer is 0. For example, if b is 9 then a would be -9. Adding these together equals 0.
Answer:
x = -1
Step-by-step explanation:
Given: 
Solve for x, When: 
Step by step:




