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Brums [2.3K]
3 years ago
5

A news report states that the 90% confidence interval for the mean number of daily calories consumed by participants in a medica

l study is (1920, 2140). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 22 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the t distribution in any calculations and round non-integer results to 4 decimal places.
1. What is the sample mean?
2. What is the margin of error?
3. What is the sample standard deviation?
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

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Step-by-step explanation:

vvzgsgygsv gdhvsysgvs gsvysvvs6sg he's) v gateways tsgsyysgd Yacc subs USB GA t gsd

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Sindrei [870]

Answer:

-20n/3n

Step-by-step explanation:

-4       1

---   /    ---

9n       15n

Keep, change, flip

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- Change the division sign to a multiplication sign

- Flip the 1/15n to 15n/1

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---   *    ---

9n       1

Cross simplify.

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15n divided by 3 is 5n.

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---   *    ---

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-20n      

---  

3n

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