This is how i solved this:
9+7=1616 divided by 12 = 1.3 (repeater)1.3 (repeater) = 1 3/10Addison should put 1 3/10 pounds of salad in each container.
Answer:
i would say 0 to help get x by itself but im not entirely sure
Step-by-step explanation:
Answer:
D (3/2
Step-by-step explanation:
<u>Simplify both side of the equation</u>: 5(4x - 10) + 10x = 4(2x - 3) + 2(x - 4)
(5)(4x) + (5)(−10) + 10x = (4)(2x) + (4)(−3) + (2)(x) + (2)(−4)
Then you distribute: 20x + −50 + 10x = 8x + −12 + 2x + −8
(20x + 10x) + (−50) = (8x + 2x) + (−12 + −8)
Combine like terms: 30x + −50 = 10x + −20
30x - 50 = 10x - 20
<u>Subtract 10x from both sides</u>: 30x − 50 − 10x = 10x − 20 − 10x
20x - 50 = -20
<u>Add 50 to both sides</u>: 20x - 50 + 50 = -20 + 50
20x = 30
<u>Divide both sides by 20</u>: 20x / 20 = 30 / 20
<em>x = 3/2</em>
<em />
Boom! I hope that helped :)
The complete question in the attached figure
we know that
perimeter=24 ft
[the perimeter of a rectangle]=2*8+2*x-----------> 16+2x
24=16+2x-------> 2x=24-16----------> 2x=8----------> x=4 ft
the answer is
the option C) x=4 ft
Answer:
And we can find this probability using the complement rule and the normal standard distribution and we got:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the number of attacks of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the complement rule and the normal standard distribution and we got: