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3 years ago

N + 1 - 3N = 9 - N (IN A TEST)

Mathematics

2 answers:

rjkz [21]3 years ago

8 0

Answer:

N= -8

Step-by-step explanation:

My name is Ann [436]3 years ago

8 0

N=-8
hope this helps!!:)

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Apply the Pythagorean Theorem to find the distance between points A and B

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The answer is b, hope I helped :)

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3 years ago

The width of a rectangular rug is 7 feet and the length of its diagonal is 25 feet. What is the area?

Vika [28.1K]

A=168 ft²
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3 years ago

A right triangle has side lengths a, b, and c as shown below.

Musya8 [376]

Answer:

$\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}$

Step-by-step explanation:

Given that

A right triangle has side lengths a, b, and c

Because you did not attached photo of the right triangle so I will assume that:

Side a is the adjacent (A)
Side b is the opposite (O)
Side c is the hypotenuse (H)

(Please have a look at the attached photo)

To solve for the trigonometric functions of x, we need to recall the ratios they represent as shown below.

$\sin x = \frac{O}{H}\\\cos x = \frac{A}{H}\\\tan x = \frac{O}{A}$

EX: the sine of x is equal to the side opposite of angle x over the hypotenuse. Hence, we have the expressions of the trigonometric functions as shown below:

$\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}$

Hope it will find you well

4 0

3 years ago

Draw a right triangle with one leg value is 4 and the other leg value is 3. Use the triangle to find the exact values of the six

Nina [5.8K]

Step-by-step explanation:

Draw a right triangle with one leg value is 4 and the other leg value is 3

The triangle is attached below

To find hypotenuse , use Pythagorean theorem

$c^{2} =a^{2} +b^{2} \\c^{2} =3^{2} +4^{2} \\\\c^{2} =25 \\\\c=\sqrt{25} =5$

opposite side = 4, adjacent side =3 and hypotenuse = 5

Apply trigonometric ratios

$sin(A)=\frac{opposite}{hypotenuse}=\frac{4}{5}$

$cos(A)=\frac{adjacent}{hypotenuse}=\frac{3}{5}$

$tan(A)=\frac{opposite}{adjacent}=\frac{4}{3}$

$cosec(A)=\frac{hypotenuse}{opposite}=\frac{5}{4}$

$sec(A)=\frac{hypotenuse}{adjacent}=\frac{5}{3}$

$cot(A)=\frac{adjacent}{opposite}=\frac{3}{4}$

4 0

4 years ago

I require assistance if anyone were to answer correctly they get marked brainliest

CaHeK987 [17]

4x + 8y = -40

if x = -6

4(-6) + 8y = -40

-24 + 8y = -40

8y = -40 + 24

8y = - 16

y = -16/8

y = -2

8 0

3 years ago

Read 2 more answers