Answer:
27
Step-by-step explanation:
Givens
b1 = 13
b2 = ?
h = 6
Area = 120
Formula
Area = (b1 + b2) * h/2 Multiply by 2
2Area = (b1 + b2)*h Divide by h
2Area/h = b1 + b2 Subtract b1 from both sides
2Area/h - b1 = b2
Solution
2*120 / 6 - 13 = b2
40 - 13 = b2
b2 = 27
It is always handy to solve an equation in the form that finds the unknown on one side. It makes the solution much easier.
<span>2x/4x+2 x 14 x+7/6 is unclear. Do you mean 2/4x, or do you mean 2x
-------- ??
4x+2
Use parentheses to make things clearer.
I will assume that you meant to write
2x
--------- * 14x + 7/6
4x + 2
but am very much unsure if this is correct or not.
Perhaps you meant
</span>2x/(4x+2) times 14(x+7/6)
<span>
This comes out as follows:
2x * 14 (x + 7/6) 28x(x + 7/6) 14x(x + 7/6)
------------------------ = ------------------- = --------------------
4x+2 2(2x + 1) 2x + 1 after reduction.
Performing the multiplication, we get 14x^2 + 98/6
--------------------
2x+1
</span>
It appears that you're using "x" both as a variable name and as the "multiply" operator. If so, please don't! Use " * " to indicate multiplication.
<span>
</span>Please take and share a screen shot of this problem.
24,000,300
Step-by-step explanation:
you mean twenty-four million and three hundred right? or Twenty million and three hundred thousand?
because that's not possible.
Answer:
It is not possible to solve the equation y = 4x + 3. This is merely a relation between two variables x and y. The variable y is 3 greater than 4 times the variable x.
Step-by-step explanation:
What book?
Let
x-->volume of white vinegar you need to add to the mixture (measured in cups)
<span>then
the amount of the pure vinegar in the mixture will be -----> (10*0.1 + x) cups
t</span>he volume of liquid will be ---------> 10 + x
the concentration equation is-------> [(10*0.1 + x)/(10+x)]=0.50<span>multiply both sides by (10+x) and then simplify
</span>(10*0.1 + x)=(10+x)*0.50-----------> 1+x=5+0.50x-------> 0.50x=4
x=8
the answer is
<span>you need to add 8 of a cup of the pure vinegar to the mixture</span>
