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Anna007 [38]
3 years ago
6

Can Anyone Help me with this I believe I got the first one correct If not correct me please

Mathematics
2 answers:
olga_2 [115]3 years ago
7 0

Answer:

the second one I think

Step-by-step explanation:

lutik1710 [3]3 years ago
5 0

Answer:

Step-by-step explanation:

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A business rents bicycles and in-line skates. Bike rentals cost $25 a day and skates cost $20 a day. The business had 20 rentals
Lena [83]
25x+20y=455
x+y=20


20x+20y=400
-25x-20y=-455
-5x=-55
x=11
11+y=20
y=9

Solved it as well, sorry if I wasn't supposed to

6 0
3 years ago
Need help on 15 and 16 PLEASEE!!!
melisa1 [442]

Answer:

Part 15) The next three terms are 5/8,3/4 and 7/8

Part 16) The 37th term is -35.5

Step-by-step explanation:

we know that

In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant and this constant is called the common difference (d)

Part 15) Find the next three terms of the arithmetic sequence

\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},...

so

a1=1/8\\ a2=1/4\\ a3=3/8\\ a4=1/2\\ a2-a1=1/4-1/8=1/8\\ a3-a2=3/8-1/4=1/8\\ a4=a3=1/2-3/8=1/8

The common difference is equal to

d=1/8

<u><em>Find the next three terms of the arithmetic sequence</em></u>

<u><em>Find a5</em></u>

a5=a4+d ----->a5=1/2+1/8=5/8

<u><em>Find a6</em></u>

a6=a5+d ----->a6=5/8+1/8=3/4

<u><em>Find a7</em></u>

a7=a6+d ----->a7=3/4+1/8=7/8

therefore

The next three terms are

5/8,3/4 and 7/8

Part 16) what is the 37th term of the arithmetic sequence

4.1,3,1.9,0.8,...?

so

a1=4.1\\ a2=3\\ a3=1.9\\ a4=0.8

a2-a1=3-4.1=-1.1\\ a3-a2=1.9-3=-1.1\\ a4=a3=0.8-1.9=-1.1

The common difference is equal to

d=-1.1

We can write an Arithmetic Sequence as a rule

an=a1+d(n-1)

substitute the values

an=4.1-1.1(n-1)

For n=37

substitute

a37=4.1-1.1(37-1)

a37=4.1-1.1(36)

a37=-35.5

4 0
3 years ago
Miguel has two same size rectangles divivded into the same number of equal parts. One rectangle has 3/4 of the parts shaded, and
ivanzaharov [21]
Bother rectangles could be divided into 8 parts.
6 0
3 years ago
Find the area of the region enclosed by the graphs of the functions
Vaselesa [24]

Answer:

\displaystyle A = \frac{8}{21}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Functions
  • Function Notation
  • Graphing
  • Solving systems of equations

<u>Calculus</u>

Area - Integrals

Integration Rule [Reverse Power Rule]:                                                                 \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                      \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                          \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

<u>Step 3: Find Area of Region</u>

<em>Integration</em>

  1. Substitute in variables [Area of a Region Formula]:                                     \displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx
  2. [Area] Rewrite [Integration Property - Subtraction]:                                     \displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx
  3. [Area] Integrate [Integration Rule - Reverse Power Rule]:                           \displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}
  4. [Area] Evaluate [Integration Rule - FTC 1]:                                                    \displaystyle A = \frac{2}{3} - \frac{2}{7}
  5. [Area] Subtract:                                                                                               \displaystyle A = \frac{8}{21}

Topic: AP Calculus AB/BC (Calculus I/II)  

Unit: Area Under the Curve - Area of a Region (Integration)  

Book: College Calculus 10e

6 0
3 years ago
For all values of x and y, which expression is equivalent to 8x + 6y? A) 2(4x + 3y) B) 2x + 3y C) 3(4x + 2y) D) 4(2x + 3y)
Reika [66]
The answer would be 2(4x + 3y) cause the 2 gets multiplied by the numbers in the parentheses so 2x4x = 8x and 2x 3y = 6y
8 0
3 years ago
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