The equation of the line that passes through (-6,0) and is parallel to the line y = 5x - 43 in slope intercept is y = 5x + 30
<em><u>Solution:</u></em>
Given that line that passes through (-6, 0) and is parallel to the line y = 5x - 43
We have to find the equation of line
Let us first find slope of line having equation y = 5x - 43
<em><u>The slope intercept form of line is given as:</u></em>
y = mx + c ------- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
On comparing equation of line y = 5x - 43 with slope intercept form y = mx + c,
we get m = 5
Thus slope of given line is 5
We know that slopes of parallel lines are equal
Thus the slope of line parallel to given line is also 5
Now let us find equation of line having slope "5" and passes through (-6, 0)
Substitute m = 5 and (x, y) = (-6, 0) in eqn 1
y = mx + c
0 = 5(-6) + c
<h3>c = 30</h3>
<em><u>Thus the required equation is:</u></em>
Substitute c = 30 and m = 5 in eqn 1
y = 5x + 30
Thus the required equation of line is found
and 
. Since I was so close, I went ahead and just solved it anyway. You can see my setup on the attached image.
