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Anestetic [448]
3 years ago
8

Last Saturday, Ben and Dominic set up a lemonade stand to help their grandmother use

Mathematics
2 answers:
qaws [65]3 years ago
8 0

Answer:

378 Lemons

Step-by-step explanation:

Because you use 2 lemons for every cup, you first need to find how many lemons per pitcher by multiplying 9 by 2 to get 18, so 18 lemons per pitcher, then multiply that by 21 because that's the total amount of pitchers to get 378 lemons

expeople1 [14]3 years ago
5 0

Answer:

378

Step-by-step explanation:

pls mark as brainlyest or thanks to pass

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X:8 16 24 32<br> Y:2 12 22 32<br> Is the relationship linear, exponential, or neither?
vladimir2022 [97]

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linear

Step-by-step explanation:

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4 years ago
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Which store has the larger median value?
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The store with the larger numbers
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3 years ago
ABC ≃DEF. Find the lengths of the given sides
GuDViN [60]

Answer:

BC = 8 and EF = 8.

Step-by-step explanation:

Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).

Set BC and EF equal to each other.

x + 6 = 3x + 2

Subtract x from both sides.

6 = 2x + 2

Subtract 2 from both sides.

4 = 2x.

Divide 2 on both sides.

x = 2.

Substitute 2 for x.

BC = 2 + 6

BC = 8

Since we already know that EF is congruent to BC, EF is also 8.

EC = 3(2) + 2

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5 0
3 years ago
Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third
asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

average=\frac{81+87+x}{3}

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87

This ine72\leq x} \leq 87quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0
3 years ago
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