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Anna35 [415]
3 years ago
9

Why might information overload be a concern for consumers who use a cell phone app to research a particular purchase? What would

you recommend that app developers do to avoid creating this problem?
Computers and Technology
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

Explanation:

Information overload is a term which is utilized to depict the trouble of understanding an issue and adequately settling on choices when one has excessively information about that issue. By and large, the term is related with the exorbitant amount of every day information. Information overload happens when the measure of contribution to a framework surpasses its handling limit. Leaders have genuinely constrained psychological preparing limit. Thus, when information overload happens, almost certainly, a decrease in choice quality will happen. This why it becomes a concern when it is not tackled wisely by not remaining focused.

Well, I would recommend the app developers to avoid the things are as follows:

• Give supporting information. - If a client needs more information, ensure it's to hand for them.

• Make it simple for the client to make a move. - If they have to finish an assignment there and afterward make it open and make it self-evident.

• Clarify what can anyone do the information. - What move should the client make? For what reason should the take it?

• Keep it important. - Information that really addresses the client's issues is more averse to overpower.

• Give adjusted information. - You should introduce the two sides of the coin as opposed to only one.

• Keep things straightforward. - The less information you present – the less demanding it is to get it.

• Keep it clear. - Simplicity and importance are great however information needs clearness to be successful

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What is the full form of bcc please tell​
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3 0
3 years ago
Read 2 more answers
Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targe
natali 33 [55]

Answer:

The C++ code is given below with appropriate comments

Explanation:

//Remove this header file if not using visual studio.

#include "stdafx.h"

//Include the required header files.

#include <iostream>

//Use for maths function.

#include <cmath>

using namespace std;

//Define main function

int main()

{

      // Define the variables

      double targetValue = 0.3333;

      double sensorReading = 0.0;

      //Perform the opeartion.

      sensorReading = 1.0 / 3.0;

      // Get the absolute floating point value and

      // Check up to 4 digits.

      if (fabs(sensorReading - targetValue) < 1E-4)

      {

             //Print equal if the values are close enough.

             cout << "Equal" << endl;

      }

      else

      {

             //Print not equal if the values are not                  

             //close enough.

             cout << "Not equal" << endl;

      }

      system("pause");

      //Return the value 0.

      return 0;

}

5 0
4 years ago
What might a programming prefer the top-down approach to programming design?
navik [9.2K]

Top down program design is an approach to program design that starts with the general concept and repeatedly breaks it down into its component parts. In other words, it starts with the abstract and continually subdivides it until it reaches the specific. Consider creating the prime factorization of a number like 1540. The steps involved might look like:

1540

2 x 770

2 x 2 x 385

2 x 2 x 5 x 77

2 x 2 x 5 x 7 x 11

Top down program design works the same way. We start with the overall objective and wind up with a series of steps needed to accomplish it.

3 0
4 years ago
How do you get a code in C to count down from 5??
Valentin [98]

Answer:

This is what the code should do:

“Lift off in T minus

5

4

3

2

1

Blast-off!”

When I run it, it just keeps printing ''Sum = 5'' forever.

Explanation:

Code:

int main(void) {

int sum = 5;  

int i;      

printf("Lift off in T minus\n");

for (i = 0; i < 5; i=i+i) {

   sum = sum - i;  

   printf("sum = %d\n",sum);  

}  

printf("Blast-off",sum);  

return 0;

5 0
4 years ago
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