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3 years ago

The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius ?

Mathematics

1 answer:

nadezda [96]3 years ago

6 0

Step-by-step explanation:

Cone Volume = 1/3 ×( π r² h) h = 2 × diameter = 2 × 2 × r

Cone Volume = 1/3 ×( π r² h) h = 2 × diameter diameter = 2r

= 2 × (2 × r)

= 4r

Cone Volume = 1/3 ×( π r² 4r)

= (4 π r³ / 3)

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Hunter did not want to spend more than 150$ for a flight from Reno to Los Angeles. Write the inequality that models this situati

Jobisdone [24]

Answer:

$(a)\ x < 150$

$(b)\ x = 149; x = 148$

Step-by-step explanation:

Given

$Amount = 150$ --- not more than

$x \to$ spending

Solving (a): Represent as an inequality

Not more than means <

So, the inequality is:

$Spending < Amount$

$x < 150$

Solving (b): The first two possible solutions

These are the numbers closest to 150 i.e. 149 and 148

Hence, $x = 149; x = 148$

7 0

3 years ago

A line passes through the points (2,21) and (8,27). Write a linear function rule in terms of x and y for

tatiyna

We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19

6 0

2 years ago

Read 2 more answers

(SUPER EASY ANSWER QUICK 30 POINTS!)

harina [27]

$\frac{35}{4}$ feet below the surface

adding the 2 quantities

3 $\frac{1}{2}$ + 5 $\frac{1}{4}$

= (3 + 5 ) + ( $\frac{1}{2}$ + $\frac{1}{4}$ )

= 8 + ( $\frac{2}{4}$ + $\frac{1}{4}$ )

= 8 + $\frac{3}{4}$ = 8 $\frac{3}{4}$ = $\frac{35}{4}$

3 0

3 years ago

1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c

prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

$P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}$

a) One randomly selected person preferes aisle seat with probability

$\dfrac{153}{403}$

b) Two randomly selected people both prefer aisle seat (with replacement) is

$\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}$

c) Two randomly selected people both prefer aisle seat (without replacement) is

$\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}$

8 0

3 years ago

Write the equation of the line with a slope of 3/7 passing through the point (9,-2) in standard or slope-point form? ...?

Musya8 [376]

$y-y_1=m(x-x_1)
\\
\\ m= \frac{3}{7} 
\\
\\(9,-2) \Rightarrow x_1=9,y_1=-2
\\
\\ y-(-2)=\frac{3}{7} (x-9)
\\
\\y+2=\frac{3}{7}x-\frac{27}{7}
\\
\\y=\frac{3}{7}x-\frac{27}{7}-2
\\
\\y=\frac{3}{7}x-\frac{41}{7}$

7 0

3 years ago