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antiseptic1488 [7]
3 years ago
5

Hunter did not want to spend more than 150$ for a flight from Reno to Los Angeles. Write the inequality that models this situati

on and determine the first two possible solutions
Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

(a)\ x < 150

(b)\ x = 149; x = 148

Step-by-step explanation:

Given

Amount = 150 --- not more than

x \to spending

Solving (a): Represent as an inequality

Not more than means <

So, the inequality is:

Spending < Amount

x < 150

Solving (b): The first two possible solutions

These are the numbers closest to 150 i.e. 149 and 148

Hence, x = 149; x = 148

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kari74 [83]
If he plays 3 matches a week for 9 weeks, you have to multiply 3&9.
3*9=27
Daniel will have played 27 tennis matches by the end of the 9 weeks.
Hope this helps:)
5 0
3 years ago
Read 2 more answers
Nick can run the 440 yard dash in 55 seconds, and Jack can run it in 88 seconds. How great a handicap must Nick give Jack for th
Zepler [3.9K]
Jack --> 440 = rate * 88Jack --> 5 yrds/sex = rateJack in 55 seconds --> distance = 5 * 55 = 275 yrds440 - 275 = 165 yards handicap.
8 0
3 years ago
Priya and Han both factored the number 80. Priya says they should both get the same answer even if they started with different f
meriva

Answer:

Priya is right.

Step-by-step explanation:

The factors of 80 is 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factor pairs of 80 are

1 x 80, 2 x 40, 4 x 20, 5 x 16 and 8 x 10

If Priya picks 2 x 40, then it's prime factorisation will be, 2 x 2 x 2 x 2 x 5 = 2⁴ x 5.

If Han picks, 5 x 16 = 5 x 2 x 2 x 2 x 2 = 5 x 2⁴ = 2⁴ x 5. This is the same.

Therefore, Priya is correct, because the factors of 80 are always the same, therefore which ever you start with, you'd always get the same answer.

4 0
2 years ago
B)______ is the number of times a particular value occurs in a given data​
posledela

Answer:

<u>the frequency</u> is the number of times a particular value occurs in a given data.

5 0
2 years ago
A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the followi
Stels [109]

Answer:

One of the balls is yellow: 0.36

At least one ball is red:0.73

Both balls are green:0.3

Both balls are of the same color:0.266

Step-by-step explanation:

To get the probability equally likely of choosing balls we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

#of equally likely possibilities of the first experiment is 1+2+3=6

#of equally likely possibilities of the second experiment is 1+2+3 -1 =5 ( no replacement)

We choose 2 balls so we have to multiple  or add the probability of the 2 experiments,  that depends on the case

One of the balls is yellow:

1 experiment P{ One of the balls is yellow }= 1/6

2 experiment P{ One of the balls is yellow }= 1/5

P{ One of the balls is yellow }= 1/6+1/5=11/30

At least one ball is red:

1 experiment P{ One of the balls is red }= 2/6

2 experiment P{ One of the balls is red }= 2/5

P{ One of the balls is yellow }= 2/6+2/5=22/30

Both balls are green:

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 3/5

P{ Both balls are green }= 3/6*3/5=0.3

Both balls are of the same color

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 2/5

P{ Both balls are green }= 3/6*2/5=0.2

1 experiment P{ Both balls are red }= 2/6

2 experiment P{ Both balls are red }= 1/5

P{ Both balls are red }= 3/6*3/5=0.066

Both could happens so we add the probabilities

P{ Both balls are of the same color }=0.2+0.066=0.266

8 0
3 years ago
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