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2 years ago

14

How were shapes named?

2 answers:

Vinvika [58]2 years ago

6 0

Answer:

Most shapes get their name based on the number of sides they have. Shapes also get their names from many different languages. Sometimes shapes don't have to get their name from the number of sides they have. They can get their name out of what they look like or what they smell like.

Step-by-step explanation:

PilotLPTM [1.2K]2 years ago

4 0

Answer [5]

<em>Hi, I'm Lilo, and I'm here to help you!</em>

<em>Most shapes get their name </em><em>based on the number of sides they have</em>.

<em>Maybe the "More Info" section will help.</em>

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~`

More info:

<em>Most shapes get their name based on the number of sides they have. Shapes also get their names from many different languages.</em>

<em />

<em>Sometimes shapes dont have to get their name from the number of sides they have. They can get their name out of what they look like or what they smell like.</em>

<em />

<em>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</em>

<em>Last messages:</em>

<em></em>

<em>I hope this helps :D</em>

<em>Have a great morning/afternoon/night!</em>

<em />

<u><em>- [Lilo2was2lost]</em></u>

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Given segments AB and CD intersect at E.

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$\mathbf{AB = 3\sqrt{2}}$
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<u>(a) Length of AB</u>

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

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