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3 years ago

Brainlies please give me one 100 pontes if you give me a brainlies (give me a brainlies)

Mathematics

2 answers:

Crazy boy [7]3 years ago

3 0

Answer:

ok i will

Step-by-step explanation:

none

Leviafan [203]3 years ago

3 0

Answer:

i hope

Step-by-step explanation:

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The answer is A -6,-4

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Add. −65+(−43) 22 −22 −108

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3 years ago

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torisob [31]

Step-by-step explanation:

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Solve the linear differential equation 2xy' + y = 2√x

77julia77 [94]

Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

$\frac{dy}{dx}+P(x)y=Q(x)$

For this case, we can rewrite the equation as:

$\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}$

Here $P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}$

To find the solution (y(x)), we can use the integration factor method:

$Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx$

Then $F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}$

So, we can find:

$y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C$

Suppose that $x\in \double R$ , then $\sqrt{|x|}=\sqrt{x}$ , and we find:

$y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}$

To check our solution is right or not, put your y(x) back to the ODE:

$y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}$

$2xy'=\frac{x-C}{\sqrt{x}}$

$2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}$

(it means your solution is right)

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2 years ago

4/6 + 1/2 hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

tresset_1 [31]

Answer:

7/6 or 1 1/6

Step-by-step explanation:

4/6 + 1/2

= 4/6 + 3/6

= 7/6 = 1 1/6

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3 years ago

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