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aksik [14]
3 years ago
13

If the sides of square are increased by 2 meters, the area becomes 64 square meters. Find the lenght of a side of the original s

quare
Mathematics
2 answers:
weeeeeb [17]3 years ago
8 0

Answer:

The length of a side of the original square is 6 meters long.

Step-by-step explanation:

First, you need to know that finding the area of a square means multiplying two sides together. You also need to know that a square has four equal sides, meaning that the area is a square of a number. This means that since the area of the new square is 64 square meters, then finding a side length would mean finding the square root of 64. Using a calculator, you see that the square root of 64 is eight. This means that the second square has a side length of 8 meters.

Next, the problem tells you the sides of the new square were increased by 2 meters. All you would have to do is subtract 8 by two, which equals six. That being said, the length of a side of the original square would be six meters.

+The area of the original square would be 36 meters, because 6 times 6 (side times side) equals 36.

zepelin [54]3 years ago
8 0
The length of one side Is 6 meter long
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The proportion of items in a population that possess a specific attribute is known to be 0.45. a. If a simple random sample of s
yanalaym [24]

Answer: 0.05

Step-by-step explanation:

  • Sampling error is the error occurs by considering sample for study instead of entire population.

Given : The proportion of items in a population that possess a specific attribute is known to be 0.45.

Sample size : n= 100

Sample proportion of items in a population that possess a specific attribute : \hat{p}=0.48

Now, the formula to find the sampling error :

\text{Sampling error} =\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

\text{Sampling error} =\sqrt{\dfrac{0.48(1-0.48)}{100}}

=\sqrt{\dfrac{0.48(0.52)}{100}}\\\\=\sqrt{0.002496}\approx0.05

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4 0
3 years ago
Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x
Radda [10]

Answer:

{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is  \dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes arey = k \pm \dfrac{b}{a}(x - h)

1. Calculate h and k. The hyperbola is symmetric about the origin, so  

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3  

3. For 'b': The equation for the asymptote with the positive slope is  

y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x

Thus,  asymptote has the slope of

\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}

4.  The equation of the hyperbola is

\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

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3 years ago
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Step-by-step explanation:

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