The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by
![f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
So for f(x) = x² on [1, 5], the AROC of f is
![f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5B1%2C5%5D%7D%20%3D%20%5Cdfrac%7B5%5E2-1%5E2%7D%7B5-1%7D%20%3D%20%5Cdfrac%7B24%7D4%20%3D%20%5Cboxed%7B6%7D)
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-TetraFish
Answer:
a) 9*π or approx 28.26
b) ∡CRB=100°
Step-by-step explanation:
As known for secants crossing each other inside the circle is coorect the following:
BR*RD=AR*RC
=> 3*RD=4*4.5
RD=6
The diameter of the circle with center P is BD=BR+RD=3+6=9
So the radius of the circle is D/2=9/2=4.5
As known the circumference of any circle can be calculated as
C=2*π*r , where r is the circle's radius
So C=2*4.5*π=9*π= approx 3.14*9=28.26
b) ∡CRB=∡ARD= (arcBC+arcAD), where arcBC and arcAD smaller arcs
BD is the circle's diameter, so arc BD=180°
So arcBC=180°-arcCOD=180°-100°=80°
Similarly arcBD=180°
arcAD=180°-arcBSA=180°-60°=120°
∡CRB= (80°+120°)/2=100°
Hello how are you doing so the answer for this question is going to be maybe it’s going to be A
