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4vir4ik [10]
3 years ago
7

PLEASE HELP ASAP! The quotient of two rational numbers is positive. What can you conclude about the signs of the dividend and th

e divisor?
Mathematics
2 answers:
miskamm [114]3 years ago
4 0

Answer:

Step-by-step explanation:

Both dividend and divisor have same sign -  

(i) both have positive sign  or

(ii) both have negative sign

Eg:

(i) \frac{10}{2}=5

(ii)\frac{-10}{-2}=5

Anon25 [30]3 years ago
3 0

Answer:

They either both have to be positive or negative.

Step-by-step explanation:

1 / 1 = 1

-1 / -1 = 1

This gets you positive, when both dividend and divisors are positive or negative.

-1 / 1 = -1

1 / -1 = -1

This gets you negative, when both dividend and divisors are different signs.

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What is the geometric mean of 2 and 8?
asambeis [7]

Answer:

The geometric mean of 2 and 8 comes out to equal 4.

Step-by-step explanation:


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3 years ago
If r = 9, b = 5, and g=-6, what does (r+b-g) (b+g) equal?<br> O-20<br> O-8<br> 08<br> O 19<br> O 20
Colt1911 [192]

Answer:

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7 0
1 year ago
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

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hi!

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3 years ago
How do you round 282 to the nearest whole number
dimaraw [331]

Answer:

the answer is itself 282

Step-by-step explanation:

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