4x+y=16 multiply both sides by -3 and will get
2x+3y=-2
-12x -3y = -48
2x +3y = -2
--------------------------
-10x 0 = -50
-10x = -50
x = -50/(-10) = 5
x = 5
4x+y=16
4*5+y=16
20+y=16
y = 16-20
y = -4
x = 5
y = - 4
hope helped
For the case of a line through
(
2
,
7
)
and
(
1
,
−
4
)
we have
slope
m
=
Δ
y
Δ
x
=
−
4
−
7
1
−
2
=
−
11
−
1
=
11
Using the point
(
2
,
7
)
we can write the equation of the line in point slope form as:
y
−
7
=
m
(
x
−
2
)
where the slope
m
=
11
.
That is:
y
−
7
=
11
(
x
−
2
)
To get point intercept form, first expand the right hand side so...
y
−
7
=
11
x
−
(
11
⋅
2
)
=
11
x
−
22
Then add
7
to both sides to get:
y
=
11
x
−
15
=
11
x
+
(
−
15
)
This is point intercept (
y
=
m
x
+
c
) form with slope
m
=
11
and intercept
c
=
−
15
.
If you're asking for extrema, like the previous posting
well

like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points
and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4
f(0) = 0 <---- only maximum, and thus absolute maximum
f(4) ≈ - 0.19 <---- only minimum, and thus absolute minimum
My answer is the 2nd option.
Without changing the compass setting from the previous step, place the compass on point P. Draw an arc similar to the one already drawn.
Parallel lines are lines that do not meet. In this figure, point P is the point where the 2nd line can be drawn and become parallel to line AB.
Answer:
14
Step-by-step explanation:
64-8=56
56/4=14