The answer would be 11 because the x's 9 doesnt have to move because they're on the same point. If you take 7 away from -7 you get zero. Add 4 to that 7 and you get 11. Make sesnse?
Hope this helped!
Answer:

Step-by-step explanation:
The population of a city is 250,000 and the annual growth rate is 2.2%
General equation for exponential growth is

Where y is final population and P is the initial population
'r' is the rate of growth and x is the number of years
p = 25000 and r= 2.2%= 0.022. Replace all the values in the general equaiton


125 = 5^3 = 25 * 5

The simplification you are trying to do involves finding the prime factorization of a number. Since 125 is not divisible by 2, move on to 3. 125 is also not divisible by 3, so move on to 5. Then 125/5 = 25, and 25/5 = 5, so 125 = 5^3. The prime factorization of 125 is 5^3.
Answer:

Step-by-step explanation:
Given

Required
Find f(x - 4)
Substitute x - 4 for x

Expand

Collect like terms


Answer:
I disagree with both Andre thinks exponents
are just a different way of writing
multiplication of two numbers. Elena
calculates 28 to the power of two rather than 2 to the power of 28.
Step-by-step explanation:
Correct because I have on answer key.