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3 years ago

CAN I HAVE HELP!!!!!!!!!!!

Mathematics

2 answers:

Olin [163]3 years ago

8 0

Y=x + 490 would be the answer to this!!!

horsena [70]3 years ago

6 0

The line of best fit would be y = x + 490

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Evaluate the integral by making an appropriate change of variables.

VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

u = y + x

v = y - x

Solving for x and y, we would have

x = (u - v)/2

y = (u + v)/2

in which case the Jacobian and its determinant are

$J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12$

The trapezoid R has two of its edges on the lines x + y = 8 and x + y = 9, so right away, we have 8 ≤ u ≤ 9.

Then for v, we observe that when x = 0 (the lowest edge of R), v = y ; similarly, when y = 0 (the leftmost edge of R), v = -x. So

-x ≤ v ≤ y

-(u - v)/2 ≤ v ≤ (u + v)/2

-u + v ≤ 2v ≤ u + v

-u ≤ v ≤ u

So, the integral becomes

$\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du$

$=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du$

$=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du$

$=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}$

4 0

3 years ago

If Gary is 11 years old how old are each of the family members

Korolek [52]

Answer:

everyone except his smaller siblings will be older than him

Step-by-step explanation:

if you need the correct answer say the full question you

dumb

3 0

3 years ago

Alan sells custom made kites online. He makes a flat profit of $20 per kite, but he pays $20 per day for his website. Write an i

Strike441 [17]

20x+20y=900
I hope that helps. You'll have to isolate each variable. X= kite, y=website.

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to 2(3g – 4) - (8g + 3)?

Brilliant_brown [7]

Answer:

The Answer is D

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Show work to triangles 2 and 3 explaining why they are right triangles

olganol [36]

Answer:

Step-by-step explanation:

In order for a triangle to be a right triangle, it has to fit into Pythagorean's Theorem:

$a^2+b^2=c^2$ where c is the hypotenuse.

We need to figure out which is the longest side in each of those triangles and that is the hypotenuse.

In the first set, the sqrt of 443 is 21.04, but that is not the longest side; 24 is. So the Theorem formula for that is:

$\sqrt{443}^2+17^2=24^2$ which gives us

443 + 289 = 576, but 732 does not equal 576, so that one is not right.

In the second set, the sqrt of 725 is the longest side, so that formula is:

$\sqrt{725}^2=14^2+23^2$ which gives us

725 = 196 + 529, and 725 does equal 725, so that one is right.

In the third set, the sqrt of 890 is the longest side, so:

$\sqrt{890}^2=19^2+23^2$ , which gives us

890 = 361 + 529, and 890 = 890, so that is a right triangle as well. That's how you know those are right, compared to the first one that is not.

6 0

3 years ago