108=2x-4(2x-9)
108=2x-8x+36
108=-6x+36
-36 -36
72=-6x
72/-6=-6x/-6
-12=x
Consequently, t<span>he limit of
as x approaches infinity is
.
In other words,
approaches the line y=x,
</span><span>
so oblique asymptote is y=x.
I'm Japanese, if you find some mistakes in my English, please let me know.</span>
Answer:
v=πr^2h
v/πr^2=h
Step-by-step explanation:
Answer: 59/3k+14
Step-by-step explanation: