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2 years ago

Find the maximum value of

Mathematics

1 answer:

noname [10]2 years ago

6 0

Answer:

(3, 1)

Step-by-step explanation:

Given the following constraints:

2x + 4y ≤ 10

x + 9y ≤ 12

x ≥ 0

y ≥ 0

We have to first graph the above constraints and secondly, we find the boundary points for the feasible region. This is done by plotting the graphs of 2x + 4y ≤ 10 and x + 9y ≤ 12.

From the graph, the following points satisfy the constraints:

(0,0) , (3,1) , (0,4/3) , (5,0)

Given that:

P = x + 6y

For (0, 0): P = x + 6y = 0 + 6(0) = 0

For (3, 1): P = x + 6y = 3 + 6(1) = 9

For (0, 4/3) P = x + 6y = 0 + 6(4/3) = 8

For (5, 0) P = x + 6y = 5 + 6(0) = 5

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The approximate solution of the above equation is: 55/15 (Option A). This is solved using the quartic formula, not quadratic equation.

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The quartic formula has up to four various solutions including real and imaginary numbers. Read on for more explanation.

<h3>What is the solution to the above question?</h3>

First we restate the above equation:

x²-3x+2= √(x-2) + 2

Next we remove square roots

$x^{4}$ - 6x³ + 9x² = x - 2

Add two to both sides

→ $x^{4}$ - 6x³ + 9x²+2 = x - 2 +2

→ $x^{4}$ - 6x³ + 9x²+2 = x

Subtract X from both sides

→ $x^{4}$ - 6x³ + 9x²+2 -x = x -x

→ $x^{4}$ - 6x³ + 9x²+2 - x= 0

Using the Quartic formula to solve the fourth order equation:
a $x^{4}$ + bx³ + cx² + dx + e

The resolution of x is given as:

x = 2.691085, 3.346753

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hence, the correct answer is Option A.

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1 year ago

PLZZ HELP IM IN THE NEED OF HELP LOOK IN THE PICTURE answer all 3 plzzzzz

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2 years ago

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Using statistical concepts, it is found that the number of outcomes that are possible for the complement of the union of Events J and K is of 43.

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It means that at least one of event J or event K is true, hence, it is composed by employees that are either considered support staff(less than 5 years of experience) or employees that have more than five years of experience, combining a total of 7 + 8 = 15 employees.

<h3>What is the complement?</h3>

The total number of outcomes of the union of J and K, plus the complement, add to the total number of 58, hence:

15 + x = 58

x = 43.

The number of outcomes that are possible for the complement of the union of Events J and K is of 43.

More can be learned about complementary events at brainly.com/question/9752956

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1 year ago

Subtract 8 y^2 − 5 y + 7 from 2 y^2 + 7 y + 1 1 <br><br> The answer is: −6y ^2 +12y+4

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Answer:

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Step-by-step explanation:

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3 years ago

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denis-greek [22]

Answer:

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Step-by-step explanation:

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