Find the maximum value of
1 answer:
Answer:
(3, 1)
Step-by-step explanation:
Given the following constraints:
2x + 4y ≤ 10
x + 9y ≤ 12
x ≥ 0
y ≥ 0
We have to first graph the above constraints and secondly, we find the boundary points for the feasible region. This is done by plotting the graphs of 2x + 4y ≤ 10 and x + 9y ≤ 12.
From the graph, the following points satisfy the constraints:
(0,0) , (3,1) , (0,4/3) , (5,0)
Given that:
P = x + 6y
For (0, 0): P = x + 6y = 0 + 6(0) = 0
For (3, 1): P = x + 6y = 3 + 6(1) = 9
For (0, 4/3) P = x + 6y = 0 + 6(4/3) = 8
For (5, 0) P = x + 6y = 5 + 6(0) = 5
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<h3>Answer: Negative</h3>
Reason:
The template applies to any quadratic to graph out a parabola. The coefficient for the x^2 term is 'a', and it solely determines whether the parabola opens upward or downward.
If 'a' is negative, then the parabola opens downward. The way to remember this is that 'a' being negative forms a negative frown.
On the other hand if 'a' is positive, then it forms a positive smile, and the parabola opens upward.
In this case, the points are fairly close to a parabola opening downward. This means 'a' is negative and a < 0.