All categories

3 years ago

Pat's soccer team has 15 players. 2

Mathematics

1 answer:

Arisa [49]3 years ago

5 0

Answer:

Step-by-step explanation:

Split 15 into 3 parts, and you get 5 in each group. Take 2 groups with 5 each and add them. you get 10

You might be interested in

A rectangular window has a length of 81.47 cm and a width of 34.2 cm. What is the least precise measurement of the perimeter of

alexgriva [62]

Answer:

In our case the least precise is the one with no decimal units, in our case 231 cm

Step-by-step explanation:

Perimeter=2(L+w)

where;

L=length=81.47 cm

W=width=34.2 cm

Replacing;

Perimeter=2(81.47+34.2)=231.34 cm

The most precise is the one with the highest decimal units, for example 231.34 in our case the least precise is the one with no decimal units, in our case 231

8 0

3 years ago

A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If

jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

$V=\frac{4}{3}\pi r^3$ , where r represents radius of sphere.

We know that radius is half the diameter, so radius of each candle will be $\frac{15}{2}=7.5$ cm.

$\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot (7.5\text{ cm})^3$

$\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot 421.875\text{ cm}^3$

$\text{Volume of one candle}=1766.25\text{ cm}^3$

Now we will divide 70,650 cubic cm of wax by volume of one candle.

$\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}$

$\text{Number of candles}=\frac{70,650}{1766.25}$

$\text{Number of candles}=40$

Therefore, 40 candles can be made from 70,650 cubic cm of wax.

8 0

3 years ago

What is the solution to this system of linear equations? Y-x=6 y+x=-10

snow_tiger [21]

$\left\{\begin{array}{ccc}y-x=6\\y+x=-10\end{array}\right\ \ \ |add\ both\ sides\ of\ the\ equations\\\\2y=-4\ \ \ \ |:2\\y=-2\\\\substite\ the\ value\ of\ y\ to\ second\ equation\\\\-2+x=-10\ \ \ |+2\\x=-8$

$Answer:\ x=-8\ and\ y=-2$

8 0

3 years ago

A card is selected randomly from a jar that contains 15 cards, numbered from 25 to 39. What is the probability that the card sel

VikaD [51]

Answer:

The probability that the card selected bears a number less than 34 is 0.3333.

Step-by-step explanation:

Let random variable X be defined as the number on the selected card.

There are N = 15 total cards.

The number on the cards are as follows:

S = {25, 26, 27,..., 38, 39}

The probability of an event, E is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

In this case we need to compute the probability that the card selected bears a number less than 34.

The favorable outcomes are:

s = {25, 36, 37, 38, 39}

n (X < 34) = 5

Compute the probability that the card selected bears a number less than 34 as follows:

$P(X$

$=\frac{5}{15}\\\\=\frac{1}{3}\\\\=0.3333$

Thus, the probability that the card selected bears a number less than 34 is 0.3333.

7 0

3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

3 years ago