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ExtremeBDS [4]
2 years ago
10

-3+4x-10=1/2x Please HELP

Mathematics
1 answer:
vesna_86 [32]2 years ago
3 0

Answer:

x=26/7

Step-by-step explanation:

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The formula used to calculate the value of a savings accounty =(1+)120What does theafter t years is A(t)=0.04= 1500 1+120.04frac
yulyashka [42]

We have here the formula for Compound Interest:

A=P(1+\frac{r}{n})^{nt}

Where:

• A is the accrued amount.

,

• P is the Principal (the original amount of money, the starting amount of money).

,

• r is the interest rate.

,

• n is the number of times per year compounded.

,

• t is the time in years.

When we have that n is equal to 12, we are talking here about that the amount of money is being compounded monthly (we have 12 months in a year, 12 periods, n = 12). <em>Therefore, we are dividing the rate, r, by the number of compoundings per year, n, and this is the rate per each new compounding period of time, r/n, and, in this case, n = 12 (monthly interest rate). </em>

Therefore, in few words, the fraction (0.04/12) is the monthly interest rate (option C).

[If we see the other options, we have:

• The daily interest rate would be given by 0.04/365.

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• How long the money has been in the account is time, t.

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• The starting balance in the account is the Principal, P. ]

7 0
1 year ago
Integration of ∫(cos3x+3sinx)dx ​
Murljashka [212]

Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

  • Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
  • Now , Rewrite using du and u .

\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

6 0
3 years ago
(plz help me) Chocolates cost $0.20 per ounce. Samantha spent $6.80 on chocolates. If n represents the number of ounces she boug
Lubov Fominskaja [6]

c 6.80/.20 equals n that is the answer


4 0
3 years ago
Simplify completely. (c^6/c^2)5 Enter your answer in the box.
saveliy_v [14]

the anwser is 36...................

7 0
3 years ago
Please answer right brineliest to wover right
MA_775_DIABLO [31]

Answer:

10

15

-5

-35

-30

0

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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