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SVEN [57.7K]
3 years ago
14

at a snack, a milkshake costs $1.19, a cheeseburger costs $3.19, and an order of sweet potato fries costs $2.89. austin is going

to buy this meal for 7 different people. what is the total amount it will cost him?
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
3 0

9514 1404 393

Answer:

  $50.89

Step-by-step explanation:

The total cost for one meal is ...

  $1.19 +3.19 +2.89 = $7.27

The cost of 7 of these meals will be ...

  7 × $7.27 = $50.89

It will cost Austin $50.89 for the seven meals.

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The capacity of a syringe is 0.08 liters. Convert this to milliliters.
enyata [817]

Answer:

80 millilitres (mL)

Step-by-step explanation:

Multiply by 1000 because there are 1000 mL in 1 L

8 0
3 years ago
Doing some review on PEMDAS. I just need help to know if I am on the right track with this problem.
juin [17]
Yes! You’re on the right track! You followed it perfectly!
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Well done!
3 0
2 years ago
Read 2 more answers
A person walks 2 3 of a mile in 2 9 of a hour. Which complex fraction when simplified will compute the unit rate of miles per ho
GaryK [48]
2/3  /  2/9
= 2/3 * 9/2
=18/6
=3

rate = 3 miles per hour
3 0
3 years ago
Read 2 more answers
Four times a first number decreased by a second number is - 14. The first
mel-nik [20]

Answer:

f = -5, s = -6

Step-by-step explanation:

F= first number

S= second number

4f - s = -14

f + 3s = -23

3(4f - s = -14)

12f - 3s = -42

+ f + 3s = -23

13f = -65

————

13

f = -5

4f - s = -14

4(-5) - s = -14

-20 - s = -14

+20 +20

-s = 6

———

-1

s = -6

3 0
3 years ago
Multiply. Check picture.
VashaNatasha [74]

The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

Given expression (x^2-5x+2) and (3x^2+2x+3).

To multiply these equations.

(x^2-5x+2)\times(3x^2+2x+3)

             =x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)

             =(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)

             =3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6

Combine like terms together.

             =3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6

             =3x^4-13x^3-x^2-11x+6

(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6

Hence the answer is 3x^4-13x^3-x^2-11x+6.

3 0
3 years ago
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