so I don't know but just use the internet
Answer:
hat: $12
t-shirt: $8
Step-by-step explanation:
Let the price of 1 hat = h.
Let the price of 1 t-shirt = t.
Julie: h + 2t = 28
Raj: 2h + t = 32
We have a system of 2 equations in 2 variables.
h + 2t = 28
2h + t = 32
Let's use the substitution method to solve the system of equations.
Solve the first equation for h.
h = 28 - 2t
Substitute 28 - 2t for h in the second equation.
2(28 - 2t) + t = 32
56 - 4t + t = 32
56 - 3t = 32
-3t = -24
t = 8
h = 28 - 2t
h = 28 - 2(6)
h = 12
Answer:
hat: $12
t-shirt: $8
We have that
case 1) 2x3 + 4x -----------> <span>C. cubic binomial
</span>The degree of the polynomial is 3----> <span>the greater exponent is elevated to 3
</span>the number of terms is 2
<span>
case 2) </span>3x 5 + 3x 4 + x 3--------> <span>A. Quintic trinomial
</span>The degree of the polynomial is 5----> the greater exponent is elevated to 5
the number of terms is 3
<span>
case 3) </span>x 2 + 3----------> <span>B. quadratic binomial
</span>The degree of the polynomial is 2----> the greater exponent is elevated to 2
the number of terms is 2
<span>
case 4) </span>2x 2 + x − 5 A------------> D. quadratic trinomial
The degree of the polynomial is 2----> the greater exponent is elevated to 2
the number of terms is 3
I think you are asking for two numbers, so you just have to look at the decimals.
23.7
We can use an infinite amount of numbers here, but to make it simple you can just take away 0.01 or add 0.01.
23.69
23.71
These are funny answers as well because they both round to 23.7 and meet the requirements.
Answer:
The answer is
<h2>
</h2>
Step-by-step explanation:
<h3>
</h3>
To solve the fraction reduce the fraction with d
That's we have
<h2>
</h2>
Next simplify the expression using the rules of indices to simplify the letters in the fraction
<u>For c </u>
Since they are dividing we subtract the exponents
We have
<h2>
</h2>
<u>For </u><u>e</u>
<h2>
</h2>
Substituting them into the expression we have
<h2>
</h2>
Reduce the fraction by 3
We have the final answer as
<h2>
</h2>
Hope this helps you
