In math, when you see the word "of" it usually means "times".
So the question is:
<u>2/3 times something = 10</u>
Multiply each side of the equation by 3 :
2 times something = 30
Divide each side by 2 :
<em> something = 15</em>
Answer:
the slope simplify your answer 16
Domain:
This function is a polynomial, i.e. a sum of powers of a variables, each with its coefficient. Polynomials are defined for every possible value of the variable, so the domain is the whole real number set: 
Range:
A polynomial of degree 2 represents a parabola. Since the leading coefficients, i.e. the coefficient of the term with highest degree, is positive (in this case, it's 3), the parabola is concave up. It means that it has a minimum, and it's unbounded from above. So, the range is something like 
. To find the minimum, let's start with the "standard" parabola 
, and transform it to the one of this exercise. has minimum 0, and thus its range is 
. When you multiply it times three, its shape narrows, but the range wont change: 
. Finally, when you subtract 5, you shift everythin down 5 units. This transformation affects the range, since you have 
Image of -3:
To compute 
, simply plug 
in the formula:
Numbers associated with 43:
We want to see which x value we must choose to get a y value of 43. So, the equation is
Answer:
CI 98 % = ( 3.332 ; 5.668 )
t(c) = 2.9979
Step-by-step explanation:
Confidence Interval CI 98 % then α = 2 % α = 0,02 α/2 = 0.01
Sample information:
Sample size n = 8
sample mean x = 4.5
standard deviation of sample s = 1.1 kg
degree of freedom df = n - 1 df = 8 - 1 df = 7
With α/2 0.01 and df = 7 from t-studente table we find t(c)
t(c) = 2.9979
CI 98 % = ( x ± t(c) * s/√n )
CI 98 % = ( 4.5 ± 2.9979 * 1.1/ √8 )
CI 98 % = ( 4.5 ± 3.2976/2.8228 )
CI 98 % = ( 4.5 ± 1.168 )
CI 98 % = ( 3.332 ; 5.668 )
Well 4 copies of one tenth will equal 4 tenths. so when u simplify 4 over ten (4/10 )and divide the top and bottom by the common factor which is 2 then you will get 2 fifths because 4 divided by 2 is 2 and 10 divided by 2 is 5.
