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3 years ago

Write your answer in standard form 25x +20

Mathematics

1 answer:

Gnom [1K]3 years ago

8 0

Answer:

I'm pretty sure that is in standard form

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The lengths of the diagonals of a rhombus are 2x and 10x. What expression gives the perimeter of the rhombus?

True [87]

Answer:

$P=4x\sqrt{26}\ units$

Step-by-step explanation:

we know that

The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other

Applying the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the length side of the rhombus

a and b are the semi-diagonals

we have

$a=2x/2=x\ units\\b=10x/2=5x\ units$

substitute the values

$c^2=x^2+(5x)^2$

$c^2=26x^2$

$c=x\sqrt{26}\ units$

To find out the perimeter of the rhombus multiply the length side by 4

$P=(4)(x\sqrt{26})$

$P=4x\sqrt{26}\ units$

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4 years ago

Can you help me please

STALIN [3.7K]

Answer:

Step-by-step explanation:

Here we a given a rule

It say

$x(y$ ÷ $3)^2$

And we are given the values of x and y as

x=4 and y = 9

Let us replace them in the rule we are provided with

$4(9$ ÷ $3)^2$

Applying DMAS rule, which says, first Division ollowed by Multiplication addition and then subtraction .

We first divide 9 by 3

9÷3 = 3

Hence

$4(9$ ÷ $3)^2 = 4(3)^2$

Now we square first

$3^2 = 3 \times 3 = 9$

$4(3)^2 = 4 \times 9$

$4(3)^2 = 36$

Hence our final answer will be 36

4 0

4 years ago

Write your answer in standard form 25x +20​

Write your answer in standard form 25x +20