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3 years ago

What is the solution of the system of equations shown in the graph below?

Mathematics

2 answers:

Alja [10]3 years ago

6 0

Answer:

C. $(-1,-2)$

Step-by-step explanation:

We have been given a graph of a system of equations. We are asked to find the solution for our given system.

We know that solution of the system of equation by graphing is the point, where both lines will intersect each other.

Upon looking at our given graph, we can see that both lines intersect at point $(-1,-2)$ and option C is the correct choice.

Mademuasel [1]3 years ago

3 0

Answer is (-1,-2) As where 2 lines bisect, that point be the answer. And in given scenario, both the lines bisected at (-1,-2)

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Given sin=300° , determine which of the following is an equivalent expression.

soldier1979 [14.2K]

Answer:

b. 240

Step-by-step explanation:

sin of 300 is equal to -.86

sin of 240 is equal to -.86

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2 years ago

Why can you use fraction multiplication to check the answer to a fraction division problem? How do you use multiplication to che

Vedmedyk [2.9K]

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2/3×1/6
Hint: KCC (Keep, change, change)

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3 years ago

Read 2 more answers

V = u + at<br> u = 2 a = -7 t = 0.5

VashaNatasha [74]

v= u+ at

just put value bruuhh u can't even do this? alright

v=2+ (-7)(0.5)

v= -1.5

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2 years ago

What is the measure of angle G?

zlopas [31]

Is measure of the angle G, 78?

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3 years ago

A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$

Similarly, but exchanging the role of x and y, we compute the length of BC:

$\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5$

So, the area of the rectangle is $\overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50$

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

$\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3$

$\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4$

So, the area of the portion located in the third quadrant is $\overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12$

This means that the ratio between the two area is

$\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}$

If we want this ratio to be a percentage, just make sure that the denominator is 100:

$\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%$

3 0

3 years ago