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Pavel [41]
3 years ago
5

393828294×3838383838229​

Mathematics
1 answer:
kirza4 [7]3 years ago
6 0

Answer:

I think this is the answer

Step-by-step explanation:

1511664158726899051326

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Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
10 POINTS!
katrin2010 [14]

Answer:

A = yes

B = no

C = yes

D = no

E = yes

F = yes

Hope I helped!!!

7 0
2 years ago
What is the length (magnitude) of the vector (5 -2) <br> a. √29<br> b. 5√5<br> c. 5<br> d.√2
malfutka [58]

Answer:

a. √29

Step-by-step explanation:

The formula for the magnitude of a vector is magnitude = sqrt(x^2 + y^2).

For vector (5, -2):

magnitude = sqrt(5^2 + -2^2)

magnitude = sqrt(25 + 4)

magnitude = sqrt(29)

Therefore, the answer is √29.

Hope this helped :D

8 0
3 years ago
320 students are going on a field trip 60 per bus how many buses should be ordered
EastWind [94]

Answer:

Step-by-step explanation:

320:60 you have to find the multiples I am not going to give you the full answer that is cheating

7 0
3 years ago
A bank charges a service fee of 70.50 per month for a checking acount
timurjin [86]

The months till the account stability is terrible is 1.3 months.

<h3>What is account stability?</h3>
  • In banking, the account stability is the amount of coins you have were given available on your checking or economic financial savings account.
  • Your account stability is the net amount available to you anyways deposits and credit score had been balanced with any costs or debits.
  • Your economic organization account balance suggests you methods a brilliant deal coins you have were given on your account.
  • That coins is there for you withdraw or depart in place, likely with a view to collect interest payments on it.
  • The answer isn't always truely yes, though, because of the truth your balance might not be exactly what it seems.
  • The available balance can be taken out of the account in cash at an ATM or with a economic organization teller.
  • The debit card transfers coins from the coins inside facet the checking account.

To learn more about account stability from the given link:

brainly.com/question/13387881

#SPJ13

4 0
1 year ago
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