The probability that a single radar station will detect an enemy plane is 0.65. (a) How many such stations are required to be 98
1 answer:
Answer:
4 stations
Step-by-step explanation:
If we need to be at least 98% certain that an enemy plane flying over will be detected by at least one station, we must ensure that there is at most a 2% chance that no radar stations detect the plane.
The probability that a single radar station does not detect the plane is 0.35.
For n radar stations:
Rounding up to the next whole station, at least 4 stations are needed.
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Answer:
Choice D: Perimeter = 5 + +
units
Step-by-step explanation:
point B(9, 2) , point C(4, 5), point A (1,1)
Perimeter = D( A, C) + D (A, B) + D (B, C)
where D (A, C) = distance between A and C
so...
D(A, C) = root ( (4 - 1)^2 + (5 - 1)^2) = 5 from a 3-4-5 right triangle.
D(A, B) = root( (9- 1)^2 + (2 -1)^2) = root( 64 + 1) = root(65)
D(B, C) = root( (9 -4)^2 + (2 -5)^2) = root (25 + 9) = root(34)
Perimeter = 5 + root(65) + root(34)
Perimeter = 5 + +
units
The disk method will only involve a single integral. I've attached a sketch of the bounded region (in red) and one such disk made by revolving it around the y-axis.
Such a disk has radius x = 1/y and height/thickness ∆y, so that the volume of one such disk is
π (radius) (height) = π (1/y)² ∆y = π/y² ∆y
and the volume of a stack of n such disks is
where is a point sampled from the interval [1, 5].
As we refine the solid by adding increasingly more, increasingly thinner disks, so that ∆y converges to 0, the sum converges to a definite integral that gives the exact volume V,
