Answer:
a) y = |x/2 -2| +4
b) y = |x/2 -2| +2
c) y = |(x+1)/2 -2| +3
d) y = |(x-1)/2 -2| +3
Step-by-step explanation:
To translate the function f(x) by (h, k) in the (right, up) direction, you transform it to ...
g(x) = f(x -h) +k
<u>a) one unit up</u>
Add 1 to the function value.

<u>b) one unit down</u>
Subtract 1 from the function value.

<u>c) one unit left</u>
Replace x with x-(-1).

<u>d) one unit right</u>
Replace x with x-1.

Answer:
- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that
P(8 arrive) = (0.56)^8 = 0.00967
- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.
Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be
(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).
So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079
- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,
P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)
= 1 - P(overbooked) - P(exactly booked)
= 1 - 0.00967 - 0.06079
= 0.9295.
Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.
Hope that helps!
Have a great day :P
Answer:
Step-by-step explanation:
In this case, the offspring will have two dominant traits and one recessive trait. If One of the Alleles for a traight is dominant, then the expressed traight will be dominant, assuming there is no mixing of traits. So for any offspring with these traits, they can have one or both domiant alleles for the wing shape and body color traits, but they must have both recessive alleles for the eye trait. Using a punnett square, you can find the number, which happens to be 9/64.
Answer:
£ 114
Step-by-step explanation:
From the question given above, the following data were obtained:
Price of TV = £ 1200
VAT = 20%
Amount paid = £ 300
Amount paid monthly =.?
Next, we shall determine the VAT. This can be obtained as follow:
VAT = 20% of price of TV
VAT = 20/100 × 1200
VAT = £ 240
Next, we shall determine the total cost of the TV. This can be obtained as follow:
Price of TV = £ 1200
VAT = £ 240
Total cost of TV =?
Total cost = Price + VAT
Total cost = 1200 + 240
Total cost = £ 1440
Next, we shall determine the balance amount he needs to pay. This can be obtained as follow:
Total cost = £ 1440
Amount paid = £ 300
Balance amount =?
Balance = Total cost – Amount paid
Balance = 1440 – 300
Balance = £ 1140
Finally, we shall determine the amount Harry will pay month.
Balance Amount = £ 1140
Number of months = 10
Amount paid monthly =.?
Amount paid monthly = Balance / number of month
Amount paid monthly = 1140 / 10
Amount paid monthly = £ 114
Therefore, Harry will pay £ 114 monthly.
Answer:
plus 20 or positive
Step-by-step explanation:
-60+80= 20
positive