3(2a-2)=2(3a-3) solve
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The distance travelled from the starting point is 29 km , the bearing is 344 degree
The missing diagram is attached with the answer.
<h3>What is Bearing Angle ?</h3>It is the horizontal angle between the object and another object.
It is given that the car starts from point travels for 30km on a bearing of 145, then 10 km on a bearing of 250
(a) the distance travelled from the starting point
It can be understood from the diagram that
To determine the distance , b is to determined4
By applying Cosine rule
b² = a² +c²-2ac cos
b² = 10² +30² - 2* 30*10 cos75
b² = 100+900 -600* 0.2588
b² = 100-155.2914
b² = 844.7
b = 29 km
Therefore the distance travelled from the starting point is 29 km.
(b) the bearing of the starting point from the car.
To determine the bearing ,
angle C has to be determined
By sine rule
sin C / c = sin B / b
sin C = sin 75 * 30 / 29
sin C = 0.9970
C = sin⁻¹ 0.9970
C = 85.59 degree
angle C = α +70 degree
α = 15.59 degree
Bearing = 70 + 20 + 9 0 + 90+74 = 244 degree
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