Two dimensional: it cannot be one or zero dimensional and a three dimensional point is called a vector
<span>before answering this question, we should know the properties of angles and parallel lines. For example, two angles are called interior alternate angles, if each angle is created by the existence of two parallel lines and a an another line called transversal. As for our case, 3 and 5 are alternate angles, so meas 3 = meas 5. It verifies Z test when we look at the figure.</span>
We use the distance formula for this problem.
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
The distance between point (-2,-2) and point (-2,4).
d = √[(⁻2 - ⁻2)² + (4 - ⁻2)²] = 6 units
Then, compute for 20% of 6 units:
Distance traveled = 6(0.2) = 1.2 units
Use 1.2 units as distance and the starting point (-2,-2). The x-coordinate should still be at -2 because the distance is a straight line as shown in the picture.
1.2 = √[(-2 - ⁻2)² + (y - ⁻2)²]
Solving for y,
y = -0.8
The point is found at (-2,-0.8). This is located at quadrant 3. As to the distance traveled, that would be: 1.2*6 = 6 miles. Thus, the answer is C.
The length of the line is the difference between the endpoints of the line
The length of each line to the nearest fourth inch is 0.25 inch
<h3>How to measure the length of each line</h3>
The length of the horizontal line is given as:
Length = 2 inches
This is calculated as:
Length = 3 inches - 1 inch
Length = 2 inches
8 lines are to be drawn between the 1 inch and 3 inches point.
So, the length (l) of each line is:
Simplify the fraction
Divide
Hence, the length of each line to the nearest fourth inch is 0.25 inch
Read more about line measurements at:
brainly.com/question/14366932
