We are asked to find ratio of two relative intensities. Let's start by rearranging formula for R:

For air-raid siren we have:

For jet engine noise we have:

To find out <span>many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
</span>tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]
Answer:-27/7
Step-by-step explanation:
Answer:
It is a equation
Step-by-step explanation:
Because it has an equal sign if it does not it will be a expression.
Answer:
all work is pictured and shown