Answer:
I think 2 white 4 red and that's all I know or I think I know
Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
C is the correct answer
good luck
Answer:
7A - 42
Step-by-step explanation:

Answer:
She has 90.96 miles of the trail to hike.
Step-by-step explanation:
Length of the trail:
The length of the trail is of 113.7 miles.
On the first day she hiked of 1/10 the distance of the trail.
Thus:

On the first day she hiked 11.37 miles.
On the second day she hiked the same distance as the first day.
Also 11.37 miles on the second day, and thus, 2*11.37 = 22.74 miles on the first two days.
How much of the trail does she have left to hike?
113.7 - 22.74 = 90.96
She has 90.96 miles of the trail to hike.