Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13
Answer: $80
Step-by-step explanation:
Given: The amount earned by Fadil on selling 14 televisions= $1400
Therefore, the amount he earned on selling 1 television=
Since, he sold televisions with extended warranty and he earns $20 additional for it.
Then, the fixed amount Fadil earns for each television=
Hence, Fadil earns $80 as the fixed amount for each televison.
Answer:
-8,6
Step-by-step explanation:
from what i can tell this is a 1D problem. |E-G|=7, and E=-1, so -1-G=+-7. G=-8 or 6
Answer:
7 19/42
Step 1:
Convert the mixed fractions into improper fraction (Denominator will be same)
2x7+2= 16/7
5x6+1=31/6
Step 2:
LCM of 6 and 7 are 42
Step 3:
217+96/42= 313/42
Step 4:
Covert to mixed fraction so the answer is 7 19/42
