3 years ago

Please explain and solve!!! You won't get points unless you explain!!!

1 answer:

4 0

Area of a rectangle of length L and width W is A = LW.

Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.

60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.

Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.

Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.

The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)

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Find an<br> equation for the line through (-6, 3) and<br> parallel to y = 3x + 1.

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Since this line is parallel to y = 3x + 1 their slopes are equal. The slope is equal to 3. The line is also passing the point (-3,4).

This is the format of the line parallel to y = 3x + 1

y = 3x+ b

This line passes through point (-3, 4)

Replacing the values of y and x coming from the coordinates of (-3, 4)

4 = 3 * (-3) + b

Solving for the y-intercept b

4 = -9 + b

b = 4 + 9