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ziro4ka [17]
3 years ago
11

Arline's in Aplus bar always the same distance apart and they never me

Mathematics
1 answer:
Alja [10]3 years ago
8 0

Answer:

Step-by-step explanation:

sorry cannot help you

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Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
irinina [24]

Answer:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0
3 years ago
Use the equation y+5=x/4 to fill in the missing values in the table below
-Dominant- [34]

Answer:

  1. .
  2. -2
  3. -5
  4. 20
  5. -12

Step-by-step explanation:

hope it helps

5 0
3 years ago
Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aliina [53]

Answer:

16

Step-by-step explanation:

Solve 5 to the power of x minus 3 to the power of x when x=2.

So, you do 5 to the power of 2 minus 3 to the power of 2, which is 25-9=16

8 0
3 years ago
Read 2 more answers
1. Solve the system of equations by graphing:
rjkz [21]

Answer:


Step-by-step explanation:

y = -3x - 3


m = -3_______


b = -3________  

y = 2x + 2


m = 2_______


b = _2_______


SOLVE NOW   :  -3x - 3  = 2x + 2


- 5x = 5

x = -1

subst in y : y = 2(-1)+2 = 0

the solution is : ( - 1 , 0 )

y = -3x- 3 an equation for the line 'red'    

y = 2x+2 an equation for the line 'bleus'


3 0
3 years ago
Carnival T charges an entrance fee of $7.00 and $0.50 per ticket for the rides. Carnival Q charges an entree fee of $12.00 and $
FrozenT [24]

Answer:

$30

Step-by-step explanation:

Calculation for the tickets that must be purchased for Carnival T and Carnival Q to be the same

Based on the information given let x be the number of ticket to be purchased .

Carnival T entrance fee= $7.00

Ride= $0.50 per ticket

Carnival Q entree fee =12.00

Ride= $0.25 per ticket

Tickets=$7.00 + ($0.50* x) = $12.00 + ($0.25* x)

.25 x = 5.00

Hence:

x=$.25+$5.00

×=$30

Therefore the amount of tickets that must be purchased in order for the total cost at Carnival T and Carnival Q to be the same will be $30

3 0
3 years ago
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