Ask question

Ask question

All categories

4 years ago

13

The total value of the dimes and quarters in a bank is $23.70. There are eight fewer dimes than quarters. Find the number of dim

es in the bank

1 answer:

Vinvika [58]4 years ago

8 0

Answer:

what i have to say is try to use a caculator lol

Step-by-step explanation:

You might be interested in

Which statement is true?

Zepler [3.9K]

Answer: A

Step-by-step explanation:

Square root of 35 is 5.9161

4 0

3 years ago

The husband and wife artistic team named

kvv77 [185]

Answer: 11,830

Step-by-step explanation:

3 0

3 years ago

Sally has a discount card that reduces the price of her grocery bill in a certain grocery store by 5%. if c represents the cost

MissTica

Y = sallys grocerys
x = how much sally paid

y - (.05) = x

3 0

3 years ago

ZA and B are supplementary angles. If mA (x - 9)° and

Verizon [17]

The measurement of ∠B is 168°

Given,

In the question:

Angle A and Angle B are supplementary angles.

If mA (x - 9)° and m/B= (7x + 21)°

To find the measure of ∠B

Now, According to the question;

What are supplementary angles?

Two angles are Supplementary when they add up to 180 degrees.

Now, ∠A+∠B = 180°

So,

⇒(x - 9)˚+(7x + 21)°=180°

=> 8x +12 = 180°

=> 8x = 180° - 12

=> 8x = 168

=> x = 168/8

=> x = 21

For the measure of ∠B :

∠B = (7x + 21)

∠B = 7 x 21 + 21

∠B = 168°

Hence, The measurement of ∠B is 168°

Learn more about Supplementary angles at:

brainly.com/question/13045673

#SPJ1

5 0

1 year ago

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, $\sigma=0.2$ ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

$P(x\geq 10)=0.99$

Assume the bag weight distribution is bell-shaped

Therefore,

$P(\frac{x-\mu}{\sigma}\geq 10)=0.99$

We know that

$z=\frac{x-\mu}{\sigma}$

Using the value of z

Now,

$\frac{10-\mu}{0.2}=0.99$

$10-\mu=0.99\times 0.2$

$\mu=10-0.99\times 0.2$

$\mu=9.802$

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0

3 years ago