MULTIPLE CHOICE QUESTION

Determine whether heating or cooling takes place during each process, freezing, evaporation, condensation, melting sublimation,

Sergeeva-Olga [200]

Answer :

Heating takes place during the process of Evaporation, Melting, Sublimation.

Cooling takes place during the process of Freezing, Condensation, Deposition.

Explanation :

Heating : It means thermal energy releases.

Cooling : It means thermal energy absorbs.

Evaporation : It is a type of vaporization process in which a liquid changes into gas phase by providing heat.

Melting : It is a process in which a solid changes into liquid phase by providing heat.

Sublimation : It is a process in which a solid changes directly into gas phase without passing through a liquid phase.

Freezing : It is a process in which a liquid transform into a solid phase at low temperature.

Condensation : It is a process in which a water vapor(gas) changes into liquid state at low temperature.

Deposition : It is a process in which a gas transforms directly into a solid phase without passing through a liquid phase.

3 0

3 years ago

Please somebody give me the answers

RSB [31]

Answer:

1. 9.4 grams of methane produce 25.85 grams of CO2

2.Grams of water produced = 11.81 grams

3.Mass of Methane produced by 10.1 gram of O2 = 2.52 grams

4.Amount of methane consumed = 46.9 grams

5. Grams of Co2 produced = 8.32 grams

Explanation:

Molar masses :

Methane = CH4 = mass of C + 4x (mass of H)

CH4 = 12 +4(1) = 16 grams

1 mole of CH4 = 16 gram

Oxygen O2 = 2 x (mass of O) = 2x(16) = 32 gram (1 mole of O2 =32 gram)

Carbon Dioxide =CO2 = mass of C + 2(mass of O)

= 12 + 2(16)

= 44 grams (1 mole of CO2 = 44 gram )

Water = H2O = 18 grams ( 1 mole of H2O = 18 gram)

1 mole of each molecule is equal to their molar masses

The balanced equation is :

$1CH_{4}(g)+2O_{2}\rightarrow 1CO_{2}+2H_{2}O(l)$

According to Stoichiometry :

1 mole of CH4 = 2 Mole of O2 = 1 mole of CO2 = 2 mole of H2O

1. From the equation ,

1 mole of methane produce =1 mole of CO2

16 gram of methane = 44 gram of CO2

1 gram of methane =

$\frac{44}{16}$ gram of CO2

9.4 gram of CH4 =

$\frac{44}{16}\times 9.4$ gram of CO2

= 25 .85 gram of CO2

2.

2 mole of O2 produces = 2 mole of H2O(water)

1 mole of O2 produces = 1 mole of H2O

32 gram of O2 = 18 gram of water

1 gram of O2 =

$\frac{18}{32}$

21 gram of O2 =

$\frac{18}{32}\times 21$

11.81 gram of water

3. 1 mole of CH4 = 2 mole of O2

16 gram of CH4 = 2(32) = 64 grams of O2

64 gram of O2 needs = 16 grams of CH4

1 gram of O2 needs =

$\frac{16}{64}$

10.1 gram of O =

$\frac{16}{64}\times 10.1$ of CH4

= 2.52 gram

4.

1 mole of CO2 is produced from = 1 mole of CH4

44 gram of CO2 is produced from 16 gram of CH4

1 gram CO2 =

$\frac{16}{44}$ gram of CH4

129 gram of CO2 =

$\frac{16}{44}\times 129$ gram of CH4

= 46.90 grams

5.

2 mole of O2 produce = 1 mole of CO2

2x 32 gram of O2 = 44 gram of CO2

1 gram of O2 =

$\frac{44}{64}$ of CO2

12.1 gram of O2 produce=

$\frac{44}{64}\times 12.1$ of CO2

= 8.318 gram

Note : Write the quantity give on left side of "="

write the substance asked on right side of "="

8 0

3 years ago

Which carbonate is most stable to heat?

d1i1m1o1n [39]

Answer:

B

Explanation:

bevxjs zkbxkxbxo xkd ksbslbsi ixbxksbzo

3 0

3 years ago

Read 2 more answers

If 1,2-dichloroethane has a density of 1.23 g/ml, how do you expect it to sit in a separatory funnel with an aqueous solution?

Jobisdone [24]

1,2-dichloroethane of density 1.23 g/ml would settle down an aqueous solution.

<h3>Density:</h3>

Knowing whether the aqueous layer is above or below the organic layer in the separatory funnel is crucial since it determines which layer is ultimately kept and discarded. Because immiscible solvents have different densities, they will stack on top of one another. The less-dense solution will rest on top, and the more dense one will rest at the bottom.

Due to their low density of less than 1 g/mL, the majority of non-halogenated organic solvents will float on top of an aqueous solution (if they are immiscible). One significant exception is that halogenated solvents will sink below aqueous solutions because they are denser than water (having densities greater than 1 g/mL). Except for halogenated solvents like dichloromethane, which are usually on the bottom, most organic solvents, such as diethyl ether, are on top.

Learn more about aqueous layer here:

brainly.com/question/14356327

#SPJ4

5 0

2 years ago

What is nomenclature? -,-

Kamila [148]

Answer:

the devising or choosing of names for things, especially in a science or other discipline.

Explanation:

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