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Burka [1]
2 years ago
11

If 1,2-dichloroethane has a density of 1.23 g/ml, how do you expect it to sit in a separatory funnel with an aqueous solution?

Chemistry
1 answer:
Jobisdone [24]2 years ago
5 0

1,2-dichloroethane of density 1.23 g/ml would settle down an aqueous solution.

<h3>Density:</h3>

Knowing whether the aqueous layer is above or below the organic layer in the separatory funnel is crucial since it determines which layer is ultimately kept and discarded. Because immiscible solvents have different densities, they will stack on top of one another. The less-dense solution will rest on top, and the more dense one will rest at the bottom.

Due to their low density of less than 1 g/mL, the majority of non-halogenated organic solvents will float on top of an aqueous solution (if they are immiscible). One significant exception is that halogenated solvents will sink below aqueous solutions because they are denser than water (having densities greater than 1 g/mL). Except for halogenated solvents like dichloromethane, which are usually on the bottom, most organic solvents, such as diethyl ether, are on top.

Learn more about aqueous layer here:

brainly.com/question/14356327

#SPJ4

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Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of water is produced from
krek1111 [17]

The given question is incomplete. The complete question is :

Gaseous butane reacts with gaseous oxygen gas  to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Answer: 28.0 %

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of butane}=\frac{4.65g}{58g/mol}=0.080moles

\text{Moles of oxygen}=\frac{10.8g}{32g/mol}=0.34moles

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

According to stoichiometry :

13 moles of O_2 require 2 moles of butane

Thus 0.34 moles of O_2 will require=\frac{2}{13}\times 0.34=0.052moles  of butane

Thus O_2 is the limiting reagent as it limits the formation of product and butane is the excess reagent.

As 13 moles of O_2 give = 10 moles of H_2O

Thus 0.34 moles of O_2 give =\frac{10}{13}\times 0.34=0.26moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=0.26moles\times 18g/mol=4.68g

{\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%

{\text {percentage yield}}=\frac{1.31g}{4.68g}\times 100\%=28.0\%

The percent yield of water is 28.0 %

6 0
4 years ago
4<br> What two particles are found in the nucleus of an atom?<br> protons<br> neutrons<br> electrons
jenyasd209 [6]
Protons and electrons i got it right
6 0
3 years ago
Two cups of coffee, one that is at 10 C and one that is 20 C, are mixed. Which statement about the temperature of the mixture is
Alenkasestr [34]
The temperature will be the average of 10 C and 20 C which is 15 C.
Energy is transferred from faster moving molecules to slower moving molecules, and the result is the average of 15°C. <span>This is just another temperature problem where you add something hot to a cold liquid and you have to calculate the final temperature. Since the energy given up by the hot coffee = energy absorbed by the cold coffee, the mass of the two fluids is the same (each is 1 cup) and both are coffee so the specific heat is the same, you get T hot - Tfinal = Tfinal - Tcold and then you solve it, you get T final = (T hot + Tcold) / 2 which is simply the average of the hot and cold temperatures.

BRAINLIEST PLS!</span>
8 0
3 years ago
Read 2 more answers
3. compared to the melting points of ionic compounds, the melting points of molecular solids tend to be ___.
Reil [10]
C) Lower, 

They're lower because molecular solids form IMF's such as Dipole-Dipole and H-Bonds, while Ionic bonds are much more powerful.
3 0
3 years ago
Read 2 more answers
A rigid 8.77L tanks contains 1.45 moles oxygen at 20°C. what is the pressure in atm?
alexdok [17]
1) use the formula PV=nRT
2) Plug in given values: P(8.77 L)= (1.45 mol)(0.0821)(293 K)
3) isolate P: P= (1.45x.0821x293)/(8.77)
4) solve: P=3.98 atm
5 0
4 years ago
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