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Burka [1]
2 years ago
11

If 1,2-dichloroethane has a density of 1.23 g/ml, how do you expect it to sit in a separatory funnel with an aqueous solution?

Chemistry
1 answer:
Jobisdone [24]2 years ago
5 0

1,2-dichloroethane of density 1.23 g/ml would settle down an aqueous solution.

<h3>Density:</h3>

Knowing whether the aqueous layer is above or below the organic layer in the separatory funnel is crucial since it determines which layer is ultimately kept and discarded. Because immiscible solvents have different densities, they will stack on top of one another. The less-dense solution will rest on top, and the more dense one will rest at the bottom.

Due to their low density of less than 1 g/mL, the majority of non-halogenated organic solvents will float on top of an aqueous solution (if they are immiscible). One significant exception is that halogenated solvents will sink below aqueous solutions because they are denser than water (having densities greater than 1 g/mL). Except for halogenated solvents like dichloromethane, which are usually on the bottom, most organic solvents, such as diethyl ether, are on top.

Learn more about aqueous layer here:

brainly.com/question/14356327

#SPJ4

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5 0
3 years ago
Is this correct im so confused.
inysia [295]

Answer:

<em>the last option!!!!</em>

Explanation:

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4 0
3 years ago
Complete the following single replacement reaction. If they don’t react, just write “NR”
Kipish [7]

Here we have to complete the given single replacement reactions.

The replacement reactions are-

1) Fe (s) + CuCl₂ (aq) → FeCl₂ (aq) + Cu (s)

2) Cu (s) + FeCl₂ (aq) → NA

3) K (s) + NiBr₂ (aq) → NA

4) Ni (s) + KBr (aq) → NiBr₂ (aq) + K (s)

5) Zn (s) + Ca(NO₃)₂ (aq) → Zn(NO₃)₂ (aq)  + Ca (s)

6) Ca (s) + Zn(NO₃)₂ (aq) → NA

The replacement reactions can be explained in light of the redox potential.

The standard reduction potential of the half cells involved in these reactions are:

Fe²⁺ + 2e → Fe (E° = -0.441V); Cu²⁺ + 2e → Cu (E° = 0.674V)

Ni²⁺ + 2e → Ni (E° = -0.23V); Zn²⁺ + 2e → Zn (E° = -0.763V)

We know the half cell reactions in which the standard reduction potentials are positive are allowed.

1) The reaction is possible as Cu²⁺/Cu and Fe/Fe²⁺ standard reduction potentials are positive.

2) The reaction is not possible as Cu/Cu²⁺ and Fe²⁺/Fe standard reduction potentials are negative.

3) The reaction is not possible as Ni²⁺/Ni standard reduction potential is negative.

4) The reaction is possible as Ni/Ni²⁺ standard reduction potential is positive.

5) The reaction is possible as Zn/Zn²⁺ standard reduction potential is positive.

6) The reaction is possible as Zn²⁺/Zn standard reduction potential is negative.

4 0
3 years ago
What is △n for the following equation in relating Kc to Kp?
Nimfa-mama [501]

Answer:

-1  

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant , 0.082057 L atm.mol⁻¹K⁻¹

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2Na_{(s)}+2H_2O_{(l)}\rightleftharpoons 2NaOH_{(aq)}+2H_2_{(g)}

<u>Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)  = (2+1)-(2+2) = -1  </u>

<u></u>

7 0
3 years ago
Mineral oil dissolves in hexane but not in ethanol
chubhunter [2.5K]
That would be correct as stated.
6 0
3 years ago
Read 2 more answers
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