The given question is incomplete. The complete question is :
Gaseous butane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If 1.31g of water is produced from the reaction of 4.65g of butane and 10.8g of oxygen gas, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.
Answer: 28.0 %
Explanation:
To calculate the moles :


According to stoichiometry :
13 moles of
require 2 moles of butane
Thus 0.34 moles of
will require=
of butane
Thus
is the limiting reagent as it limits the formation of product and butane is the excess reagent.
As 13 moles of
give = 10 moles of 
Thus 0.34 moles of
give =
of 
Mass of 


The percent yield of water is 28.0 %
Protons and electrons i got it right
The temperature will be the average of 10 C and 20 C which is 15 C.
Energy is transferred from faster moving molecules to slower moving molecules, and the result is the average of 15°C. <span>This is just another temperature problem where you add something hot to a cold liquid and you have to calculate the final temperature. Since the energy given up by the hot coffee = energy absorbed by the cold coffee, the mass of the two fluids is the same (each is 1 cup) and both are coffee so the specific heat is the same, you get T hot - Tfinal = Tfinal - Tcold and then you solve it, you get T final = (T hot + Tcold) / 2 which is simply the average of the hot and cold temperatures.
BRAINLIEST PLS!</span>
C) Lower,
They're lower because molecular solids form IMF's such as Dipole-Dipole and H-Bonds, while Ionic bonds are much more powerful.
1) use the formula PV=nRT
2) Plug in given values: P(8.77 L)= (1.45 mol)(0.0821)(293 K)
3) isolate P: P= (1.45x.0821x293)/(8.77)
4) solve: P=3.98 atm