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3 years ago

Please Help me with this question. Will give Brainllest

Mathematics

1 answer:

Wewaii [24]3 years ago

7 0

Answer:63

Step-by-step explanation:

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What is a required for the Perpendicular to Parallels Theorem to be applied?

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The best and most correct answer among the choices provided by your question is the third choice or letter C.

The condition that the lines must lie in the same plane is required for the Perpendicular to Parallels Theorem to be applied.

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3 years ago

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What is 5,000 times 5,000 i wil give brainliest if you round it to the nearest hundredth

Rom4ik [11]

Answer:

300000 lol

Step-by-step explanation:

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3 years ago

Multiply or divide two quantities by the same number is called what?

erma4kov [3.2K]

Scaling. In this process you would multiply both by the same number to create an equal ratio between the two numbers.

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4 years ago

Use the substitution method to solve the system of equations. Choose the correct ordered pair. x + 2y = 12 –x = –y – 6

LekaFEV [45]

Answer:

(8,2)

Please make sure I interpreted your system correctly below.

x+2y=12

-x=-y-6

Step-by-step explanation:

I assume the system is

x+2y=12

-x=-y-6

-----------

I'm going to multiply both sides of equation 2 by -1 giving me

x+2y=12

x=y+6

I'm now going to plug equation 2 into equation 1.

(y+6)+2y=12 I replaced x with y+6 in the first equation

y+6+2y=12

3y+6=12

3y=6

y=2

x=y+6

x=2+6

x=8

The solution is (8,2)

6 0

4 years ago

So I have this question I cannot figure out 3w+w2+1=10−w

Mandarinka [93]

Answer:

Answer: w is 1.6 or. -5.6

Step-by-step explanation:

• I guess the question asks to find the value of w

${ \rm{3w + {w}^{2} + 1 = 10 - w }}$

• arrange the equation in a quadratic equation format. i.e; ax² + bx + c = 0

${ \rm{ {w}^{2} + (3w + w) + 1 - 10 = 0 }} \\ \\ { \rm{ {w}^{2} + 4w - 9 = 0 }}$

• let's solve the equation using the quadratic formular

$\hookrightarrow \: { \tt{w = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }} \\$

a is 1
b is 4
c is -9

• Substitute following the mathematical operation rules:

${ \rm{w = \frac{ - 4 \pm \sqrt{ {4}^{2} - (4 \times 1 \times - 9) } }{(2 \times 1)} }} \\ \\ { \rm{w = \frac{ - 4 \pm \sqrt{52} }{2} }}$

• split the result:

${ \rm{either \: \{w = \frac{ - 4 + \sqrt{52} }{2} \} \: \: or \: \: \{w = \frac{ - 4 - \sqrt{52} }{2} \} }} \\ \\ { \rm{either \: \{w = 1.6 \} \: \: or \: \: \{w = - 5.6 \}}}$

4 0

2 years ago