Given:
The heat content of the pizza is Q = 500 kcal
The volume of the cold water is V = 50 L
The mass of a liter of cold water is 1 kg.
Calculate the mass, M, of cold water.
M = (50 L)*(1 kg/L) = 50 kg
The specific heat of water is
c = 4.184 kJ/(kg-K)
Also,
1 kcal = 4184 J, therefore
Q = (500 kcal)*(4184 J/kcal) = 2.092 x 10⁶ J
Let ΔT = increase in temperature of the cold water, °C (same as K).
Then
Q = M*c*ΔT
or
ΔT = Q/(M*c)

Answer: The temperature increases by 10 °C (or 10 K)
Skin reproduction, which occurs over and over
Thin Skin. The epidermis differs from that of thick skin in having thinner stratum spinosum, granulosum, and corneum, and lacks the stratum lucidum (Thin Skin 1). The dermis is not arranged in ridges, but does project into the epidermis as true papillae. However, no epidermal ridges are produced