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nasty-shy [4]
3 years ago
5

Interpreting Date: Bob straps on his

Biology
1 answer:
Andreyy893 years ago
3 0

Answer:

0.3 m/s^2 is Bob's  average acceleration.

Explanation:

Initial velocity of the bob's in-lineskates= u = 0 m/s

Acceleration of the Bob= a  = ?

Final velocity of the bob's in-lineskates= v = 4.5 m/s

Duration of time in which 0 m/s velocity is changed to 4.5 m/s = t = 15 s

Using first equation of motion: v = u + at

4.5 m/s=0m/s+a\times (15 s)

5.0 m/s-0m/s =a\times 15 s

4.5 m/s=a\times 15 s

a=\frac{4.5 m/s}{15 s}=0.3 m/s^2

0.3 m/s^2 is Bob's  average acceleration.

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