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3 years ago

Please help I might fail math on god I’m not lyy

Mathematics

1 answer:

love history [14]3 years ago

5 0

Answer:in the points given, plot them first than the number in the left of the parentheses is x and the right is y.

Step-by-step explanation:

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How do I solve this question?

Yuri [45]

It's 18/100. The reduced / simplest form is 9/50 because you divide it by 2 since it's the GCS.

4 0

3 years ago

Read 2 more answers

Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

5 0

3 years ago

Help with this please. I’d appreciate if you showed the steps and the answer. Thanks!

olga55 [171]

17^2 because the equation for it is a^2+b^2=c^2 so the longest side (x) is the c so 10 i put as a and 7 i put as b. it will always be squared for pythagorean theorem so the equation will look like 10^2+7^2=17^2 and if it isn’t squared all you have to do is undo the squaring

5 0

3 years ago

Please HELLLLP! I will mark brainliest!

Anuta_ua [19.1K]

36-(b^2+c^2-2bc)=36-(b-c)^2=6^2-(b-c)^2= (6+b-c)[6-(b-c)]=(6+b-c)(6-b+c)

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3 years ago

(6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6)

Nana76 [90]

Your Answer is
7m5-3m3-3

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3 years ago

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